MATH SOLVE

4 months ago

Q:
# Multiply (x^2+3x+4)(3x^2-2x+1)

Accepted Solution

A:

Answer: option BStep-by-step explanation: To solve this exercise you must apply the proccedure shown below: - Apply the Distributive property (Remember that when you multiply two powers with the same base, you must add the exponents). [tex]b^m*b^n=b^{(m+n)}[/tex] - Add the like terms. Therefore, you obtain that the product is: [tex](x^2+3x+4)(3x^2-2x+1)=3x^4-2x^3+x^2+9x^3-6x^2+3x+12x^2-8x+4\\=3x^4+7x^3+7x^2-5x+4[/tex]