Answer:Step-by-step explanation:You must mean how to solve. I'll solve the equation for you.Explanation:√2x+3−√x+1=1√2x+3=1+√x+1(√2x+3)2=(1+√x+1)22x+3=1+2√x+1+x+12x−x+3−1−1=2√x+1x+1=2√x+1(x+1)2=(2√x+1)2x2+2x+1=4(x+1)x2+2x+1=4x+4x2+2x−4x+1−4=0x2−2x−3=0(x−3)(x+1)=0x=3andx=−1Always check the solutions in the original equation to make sure they aren't extraneous. If they do not work in the original equation, you must reject them.√2×3+3−√3+1=1So, x = 3 works. Now, let's check x = -1:√2×−1+3−√−1+1=1So, x = -1 works as well.Your solution set would be x = 3, -1Practice exercises:Solve for x.a) √3x−2−√x−2=2b) √4x+5+√8x+9=12Related questionsHow do you solve radical You must mean how to solve. I'll solve the equation for you.Explanation:√2x+3−√x+1=1√2x+3=1+√x+1(√2x+3)2=(1+√x+1)22x+3=1+2√x+1+x+12x−x+3−1−1=2√x+1x+1=2√x+1(x+1)2=(2√x+1)2x2+2x+1=4(x+1)x2+2x+1=4x+4x2+2x−4x+1−4=0x2−2x−3=0(x−3)(x+1)=0x=3andx=−1Always check the solutions in the original equation to make sure they aren't extraneous. If they do not work in the original equation, you must reject them.√2×3+3−√3+1=1So, x = 3 works. Now, let's check x = -1:√2×−1+3−√−1+1=1So, x = -1 works as well.Your solution set would be x = 3, -1Practice exercises:Solve for x.a) √3x−2−√x−2=2b) √4x+5+√8x+9=12Related questionsHow do you solve radical