MATH SOLVE

2 months ago

Q:
# (3[tex]\sqrt{x}[/tex]-1)(-5+[tex]\sqrt{x}[/tex]-9)+9

Accepted Solution

A:

Answer:Step-by-step explanation:You must mean how to solve. I'll solve the equation for you.Explanation:β2x+3ββx+1=1β2x+3=1+βx+1(β2x+3)2=(1+βx+1)22x+3=1+2βx+1+x+12xβx+3β1β1=2βx+1x+1=2βx+1(x+1)2=(2βx+1)2x2+2x+1=4(x+1)x2+2x+1=4x+4x2+2xβ4x+1β4=0x2β2xβ3=0(xβ3)(x+1)=0x=3andx=β1Always check the solutions in the original equation to make sure they aren't extraneous. If they do not work in the original equation, you must reject them.β2Γ3+3ββ3+1=1So, x = 3 works. Now, let's check x = -1:β2Γβ1+3βββ1+1=1So, x = -1 works as well.Your solution set would be x = 3, -1Practice exercises:Solve for x.a) β3xβ2ββxβ2=2b) β4x+5+β8x+9=12Related questionsHow do you solve radical You must mean how to solve. I'll solve the equation for you.Explanation:β2x+3ββx+1=1β2x+3=1+βx+1(β2x+3)2=(1+βx+1)22x+3=1+2βx+1+x+12xβx+3β1β1=2βx+1x+1=2βx+1(x+1)2=(2βx+1)2x2+2x+1=4(x+1)x2+2x+1=4x+4x2+2xβ4x+1β4=0x2β2xβ3=0(xβ3)(x+1)=0x=3andx=β1Always check the solutions in the original equation to make sure they aren't extraneous. If they do not work in the original equation, you must reject them.β2Γ3+3ββ3+1=1So, x = 3 works. Now, let's check x = -1:β2Γβ1+3βββ1+1=1So, x = -1 works as well.Your solution set would be x = 3, -1Practice exercises:Solve for x.a) β3xβ2ββxβ2=2b) β4x+5+β8x+9=12Related questionsHow do you solve radical