Write each equation in slope-intercept form of the equation of a line. Underline the slope and circle the y-intercept in each equation.3x+4y–12=02x+y=12x–y=0

Answer:A) slope of equation 3x+4y-12=0 is m= [tex]-\frac{3}{4}[/tex] and y-intercept is 3B) slope of equation 2x+y=1 is m=-2 and y-intercept is 1.C) slope of equation 2x-y=0 is m=2 and y-intercept is 0.Solution:The slope - intercept form equation of line is given asy=mx+c  --- eqn (1)Where m is the slope of the line. The coefficient of “x” is the value of slope of the line.c is the y – intercept which is the value of y at the point where the line crosses the y-axisa) Given that3x+4y-12=0    --- eqn (2)On converting equation (2) in slope intercept form, we get4y=-3x+12[tex]y=-\frac{3}{4} x+\frac{12}{4}[/tex][tex]y=-\frac{3}{4} x+3 --- eqn 3[/tex]On comparing equation (3) and (1) we get slope of equation (2) is  [tex]m=-\frac{3}{4}[/tex] and y-intercept is 3.b)  Given that2x+y=1           …(4)On converting equation (2) in slope intercept form, we gety=-2x+1       …(5)On comparing equation (5) and (1) we get slope of equation (4) is m=-2 and y-intercept is 1.C)Given that2x-y=0           …(6)On converting equation (6) in slope intercept form, we gety=2x              …(7)On comparing equation (7) and (1) we get slope of equation (6) is m=2 and y-intercept is 0.